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Derivative of Inverse Hyperbolic Trigonometry: tanh^-1(x)

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First published at 16:17 UTC on May 29th, 2020.

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In this video I go over the derivative of inverse hyperbolic tangent or tanh^-1(x) and show that it is equal to 1/(1-x^2).

View video notes on the Hive blo…

In this video I go over the derivative of inverse hyperbolic tangent or tanh^-1(x) and show that it is equal to 1/(1-x^2).

Related Videos:

Derivative of Inverse Hyperbolic Trigonometry: sinh^-1(x): http://youtu.be/s0sk4OR5hV4
Derivative of Inverse Hyperbolic Trigonometry: cosh^-1(x): http://youtu.be/ETLaLCpGwLI
Derivatives of Hyperbolic Trigonometry: tanh(x): http://youtu.be/BAPcdco7zBk
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Hyperbolic Trigonometry Identity Proof: cosh^2(x) - sinh^2(x) = 1: http://youtu.be/-UXUqIWRNEA
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Inverse Hyperbolic Trigonometry as Logarithms: sech^-1(x): http://youtu.be/cF0Pbdkae30
Inverse Hyperbolic Trigonometry as Logarithms: coth^-1(x): http://youtu.be/x0qIdT0BrHI .