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Inverse Hyperbolic Trigonometry as Logarithms: coth^-1(x)

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First published at 04:39 UTC on June 2nd, 2020.

#mathematics
#calculus
#science

Math Easy Solutions

MES

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In this video I go over converting inverse hyperbolic trig functions to logarithms and prove that the function inverse hyperbolic cotangent or coth^-1(x) is equal to 1/2·ln((x+1)/(x-1)).

Download the notes in my video: https://1drv.ms/b/s!As32ynv0L…

In this video I go over converting inverse hyperbolic trig functions to logarithms and prove that the function inverse hyperbolic cotangent or coth^-1(x) is equal to 1/2·ln((x+1)/(x-1)).

Download the notes in my video: https://1drv.ms/b/s!As32ynv0LoaIiJN9LbtYuf6NN8zJ0A?e=fvWWuT

View video notes on the Hive blockchain: https://peakd.com/hive-128780/@mes/inverse-hyperbolic-trigonometry-as-logarithms-coth-1-x

Related Videos:

Inverse Hyperbolic Trigonometry as Logarithms: sech^-1(x): http://youtu.be/cF0Pbdkae30
Inverse Hyperbolic Trigonometry as Logarithms: csch^-1(x): http://youtu.be/278-6zKYDdE
Inverse Hyperbolic Trigonometry as Logarithms: sinh^-1(x): http://youtu.be/AQT2uHlyjEs
Inverse Hyperbolic Trigonometry as Logarithms: tanh^-1(x): http://youtu.be/vfOWS8Y_rQw
Inverse Hyperbolic Trigonometry as Logarithms: cosh^-1(x): http://youtu.be/lsUcHzQAlHQ
Hyperbolic Functions - tanh(x), sinh(x), cosh(x) - Introduction: http://youtu.be/EmJKuQBEdlc
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