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Laws of Exponents: e^(x-y) = e^x/e^y

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First published at 18:32 UTC on March 18th, 2020.

#mathematics
#calculus
#science

Math Easy Solutions

MES

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In this video I go over further into the laws of exponents and prove that e^(x-y) = e^x/e^y by using the natural logarithm function and using the log rules and properties to simplify and breakdown the function to obtain the exponent law.

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Download the notes in my video: https://1drv.ms/b/s!As32ynv0LoaIg4VJPiiIa7GHatBN0w?e=Wq8NqL

View video notes on the Steem blockchain: https://steemit.com/hive-128780/@mes/laws-of-exponents-e-x-y-e-x-e-y

Related Videos:

Laws of Exponents: e^(x+y) = e^x*e^y: http://youtu.be/8z4zpIjsVjk
Laws of Logarithms: ln(x*y) = ln(x) + ln(y): http://youtu.be/2SCZzFy2b2s
Laws of Logarithms: ln(x/y) = ln(x) - ln(y): http://youtu.be/GXkyY9EmDGM
Laws of Logarithms: ln(x^r) = r*ln(x): http://youtu.be/mvJK8lQcdTY
Logarithms and their Properties - An Introduction: http://youtu.be/AZ6KKym19gI
Natural Logarithmns Defined as Integrals: Introduction: http://youtu.be/M-N2PQ5UZns
Inverse Functions Part 2: One to One Functions and the Horizontal Line Test: http://youtu.be/iSNuplUWrbA .

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